7x^2-349=0

Solution for 7x^2-349=0 equation:

7x^2-349=0

a = 7; b = 0; c = -349;
Δ = b2-4ac
Δ = 02-4·7·(-349)
Δ = 9772
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9772}=\sqrt{4*2443}=\sqrt{4}*\sqrt{2443}=2\sqrt{2443}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{2443}}{2*7}=\frac{0-2\sqrt{2443}}{14}
=-\frac{2\sqrt{2443}}{14}
=-\frac{\sqrt{2443}}{7}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{2443}}{2*7}=\frac{0+2\sqrt{2443}}{14}
=\frac{2\sqrt{2443}}{14}
=\frac{\sqrt{2443}}{7}
$